Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 69 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. (a) Letting represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis Ho and the alternative hypothesis Ha needed if we wish to attempt to provide evidence supporting the claim that exceeds 42. Answer is complete and correct. 42 versus Ha: HO: S > 42 = (b) The random sample of 69 satisfaction ratings yields a sample mean of x: 42.820. Assuming that equals 2.61, use critical values to test HO versus H at each of a = .10, .05, .01, and .001. (Round your answer z.05 to 3 decimal places and other z-scores to 2 decimal places.) Answer is complete but not entirely correct. Z = 2.55 x (c) Using the information in part (b), calculate the p-value and use it to test Ho versus H at each of a = .10, .05, .01, and .001. (Round your answers to 4 decimal places.) Answer is complete but not entirely correct. p-value = 0.0054 Since p-value 0.0054 is less than 0.10, 0.05, 0.01 ; reject HO at those levels of a but not with a = 0.10, 0.05, 0.01 = (d) How much evidence is there that the mean composite satisfaction rating exceeds 42? Answer is complete but not entirely correct. There is weak evidence