recursively and no for loops and local variable

def immutify(a : 'an int, str, list, tuple, set, or dict') -> 'an int, str, tuple, or forzenset':

IN PYTHON 3 LANGUAGE Define a recursive function named immutify; it is passed any data structure that contains int, str, tuple, list, set, frozenset, and dict values (including nested versions of any of these data structures as an argument). It returns an immutable equivalent data structure (one that could be used for values in a set or keys in a dict). The types int, str, and frozenset are already immutable. Convert a set to a frozenset; convert all the values in a tuple to be their immutable equivalents, in the same order); convert a list to a tuple (with immutable equivalents of its values, in the same order); convert a dict to tuple of 2-tuples (see the association tuple in question 2) but here with the 2-tuples sorted by the dict's keys. If immutify ever encounters a value of another type (e.g., float) it should raise a TypeError exception. The following call (with many mutable data structures) Example 1: immutify( {'b': [1,2], 'a': {'ab': {1,2}, 'aa': (1,2)}}) returns the immutable data structure (('a', (l'aa', (1, 2)), ('ab', frozenset({1, 2})))), ('b', (1, 2))) Example 2: immutify( [{1,2}, {3, frozenset([4,5])}, {6,7}]) Returns (frozenset({1, 2}), frozenset({3, frozenset({4,5})}), frozenset({6, 7}))