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refer to this function and its derivatives. locate the relative extrema and determine the concavity of f (x). y=f (x) = 1/3x^3 +2x^2 -5x +
refer to this function and its derivatives. locate the relative extrema and determine the concavity of f (x). y=f (x) = 1/3x^3 +2x^2 -5x + 1
y'= x^2 + 4x - 5 = ( x + 5) (x - 1)=> y"= 2x + 4 = 2 ( x+ 2)
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