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Register $tO contains a 32-bit binary number. For which value(s) does a performing LOGICAL shift RIGHT on this value produce the same result as an
Register $tO contains a 32-bit binary number. For which value(s) does a performing LOGICAL shift RIGHT on this value produce the same result as an ARITHMETIC shift RIGHT? That is, if we run SRL $t1, ste, 1 SRA $t2, $te, 1 in an arbitrary assembly language, which values in $tO cause the values in $t1 and $t2 to be equal? Select all that apply. Assume instructions are in the format: INST Rd, Rs, shamt where: INST instruction Rd = destination register Rs = source register shamt shift amount Hint See section 3.10 (p 75) in the textbook: https://cupola.gettysburg.edu/oer/2/e 1000 . 0110 0101...0101 0000 .0000
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