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Remarks 1. Each of ACK and CTS frames has 14 bytes, while RTS has 20 bytes. 2. PLCP long preamble length is 144 bits while
Remarks
1. Each of ACK and CTS frames has 14 bytes, while RTS has 20 bytes.
2. PLCP long preamble length is 144 bits while short preamble is 72 bits. PLCP header is of length 48 bits.
Assume that there are 1000 bytes of upper layer packet to be transmitted using RTS/CTS without fragmentation. For the calculation purpose, assume that the network does not apply any encryption scheme. Other information is provided as in the following. (30 pts) MAC Header 30 bytes 802.2 LLC 3 bytes SNAP Header 5 bytes Payload L3+ 1000 bytes FCS 4 bytes Assume that we are using 802.11b with HR/DSSS short preamble, which 1-Mbps DBSK is applied to the PLCP preamble and 2-Mbps DQBSK is applied to PLCP header. PSDU is transmitted using CCK at transmission rate of 11 Mbps. What are the NAV values filled in the (i) RTS frame and (ii) CTS frame? (iii) How much time is required to transmit the whole packet since the transmitter has waited for a DIFSStep by Step Solution
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