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Review | Constants (consistent with the right-hand rule). SOLVE The wave is traveling along the - axis. The general equations for the wave are: E

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Review | Constants (consistent with the right-hand rule). SOLVE The wave is traveling along the - axis. The general equations for the wave are: E = Emax sin(wt + ka) B = Bmax sin(wt + ka) In this example we will calculate the electric and magnetic fields of a carbon dioxide laser. The laser emits a sinusoidal To find Bmax, we use Emax = CBmax. The wavelength is ) = 10.6 x 10- m, so electromagnetic wave that travels in vacuum in the -x direction. The wavelength is 10.6 um, and the E field is along the z axis, k 27 27 rad with a maximum magnitude of 1.5 MV /m. Find the equations for 10.6x 10 6 m 5.93 x 105 rad/m the magnitudes of vectors E and B as functions of time and Also, position. W = ck = (3.00 x 108 m/s) (5.93 x 105 rad/m) = 1.78 x 1014 rad/s Substituting into the above equations with Bmax Emax 1.50X106 V/m = 5.00 x 10-3 T C 3.00x108 m/s we get E = Emax sin(wt + ka) = (1.5 x 106 V/m) sin[(1.78 x 1014 rad/s)t + (5.93 x 105 rad/m)x] B = Bmax sin(wt + ka) = (5.0 x 10-3 T) sin[(1.78 x 1014 rad/s)t + (5.93 x 105 rad/m)x] REFLECT At any point, the two fields are in phase. The wave's magnetic field has a magnitude that is about 100 times greater than the magnitude of earth's magnetic field at the surface of the earth. Part A - Practice Problem: What is Emax for the electric field of an electromagnetic wave that has a magnetic field that oscillates with a frequency of 22.6 GHz , and has a maximum strength of 1.25 x 10-4 T? Express your answer in volts per meter

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