$"$ RuO$2/$TiO$260\%40\%40070\%550)$

PG$13$

$2[20]$

$($ m$3/$mol$)$ isobutane $90$ Psat $16\mathrm{.}54$

$(10)$

$40340\%$ n$-25$ n$-$butane $$ n$-$butane $2\mathrm{.}43.$

$(10)"$