s

f(x)=1

so then if some

pinZ

unit, this then must mean that

^(-1)inZ[x]

, where

p*p^(-1)=1

, orrect?\ Obviously then

f(x)=1

and

f(x)=-1

are units, and I have Isewhere on the internet that pe laim these are the only units of

Z

out aren't simple one-term polyno Iso units? That is,

AAkinZ,f(x)

s a unit because\

f(x)=x^(k)

\

c^(k)*x^(-k)=1 no?

s f(x)=1 so then if some pZ unit, this then must mean that 1Z[x], where pp1=1, orrect? Obviously then f(x)=1 and f(x)=1 are units, and I have lsewhere on the internet that pe laim these are the only units of Z ut aren't simple one-term polyno Iso units? That is, kZ,f(x) s a unit because f(x)=xk)1f(x)=xk ckxk=1no