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ScCl3 reacts with Na2C2O4 to produce Sc2(C2O4)3 according to the equation 2 ScCl3 (aq) + 3 Na2C2O4 (aq) Sc2(C2O4)3 (s) + 6 NaCl (aq) (a)
ScCl3 reacts with Na2C2O4 to produce Sc2(C2O4)3 according to the equation 2 ScCl3 (aq) + 3 Na2C2O4 (aq) Sc2(C2O4)3 (s) + 6 NaCl (aq)
(a) Which reactant is limiting if 3.039 g of ScCl3 and 4.569 g of Na2C2O4 are allowed to react?
(b) What mass of Sc2(C2O4)3 can be produced?
(c) What mass of the excess reactant remains when the reaction is complete?
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