Score: 5/ 10 of To answered Question 11 The average fruit fly will lay 418 eggs into rotting fruit. A biologist wants to see if the average will be fewer for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 401, 388, 422, 406, 410, 411, 416, 408, 416, 395, 428, 394, 436 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use |Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv H1: 2 Select an answerv c. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ?v a f. Based on this, we should |Select an answer the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population mean is not significantly less than 418 at or = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is equal to 418. The data suggest that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is not significantly less than 418 at a = 0.05, so there is insufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is less than 418. The data suggest the populaton mean is significantly less than 418 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is less than 418."