separation process subject. Please solve it with full handwrtting solution. Kindly avoid other tutor's answer to answer this question. thank you. have a nice day.

Question 4: (15 marks) 10000 lbm at 130F containing 47.0 lb FeSO4/100lb total water is a feed. Then, the feed is cooled to 80F where FeSO4.7H20 crystals are removed. The solubility of the salt is 30.5 lb FeSO4/100 lb total water. The average heat capacity of feed solution is 0.70 btu/Ibm F. The heat of solution at 18C is -4.4 kcal/gmol (-18.4 kJ/gmol) FeSO4.7H2O. Calculate the yield of crystals and make a heat balance. Assume no water vaporized. (MW: FeSO4.7H2O = 278.02, FeSO4 = 152.0.7H20 = 126.0)