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Series - Sequences: Problem 1 (1 point) List the first five terms of the sequence: n+1 an 2n - 1 a1 a2 a3 a4 =

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Series - Sequences: Problem 1 (1 point) List the first five terms of the sequence: n+1 an 2n - 1 a1 a2 a3 a4 = and as =Series - Ratio and Root Tests: Problem 16 (1 point) 2" on Use the ratio test to determine whether E (2 )I n . n=21 converges or diverges. (a) Find the ratio of successive terms. Write your answer as a fully simplied fraction. For n 2 21, Hill % (b) Evaluate the limit in the previous parl. Enter 00 as innity and 00 as -innity If the limit does not exist, enter DNE. Ema-n+1 =C] llMI) a," (c) By the ratio test, does the series converge, diverge, or is the test inconclusive? Choose v ljm'n'q _ I'll>00 a.\" Series - Ratio and Root Tests: Problem 15 (1 point) W 745)\" Use the ratio test to determine whether I n. converges or diverges. r1214 (3) Find the ratio of successive terms. Write your answer as a fully simplied fraction. For n 2 14, me \"D (b) Evaluate the limit in the previous part. Enler 00 as innity and 00 as innity. If the limit does not exist, enter DNE, Hm'n'll : fly'00 a\" . l31+:qu _ .153. ..,, C] (c) By the ratio test, does the series converge, diverge, or is the test inconclusive? Choose v Note: You can earn 40% partial credit for 2 - 3 correct answers. Series - Ratio and Root Tests: Problem 14 (1 point) Assume that | | converges to p = . What can you say about the convergence of the given series? n=1 lim =(Enter 'inf for co.) n an is: n=1 O A. convergent O B. divergent O C. The Ratio Test is inconclusiveSeries - Sequences: Problem 2 (1 point) Calculate the first four terms of the following sequence, starting with n = 1. 6 . 4n Cn n! C2 = C3 = CA Note: You can earn partial credit on this problem.Series - Sequences: Problem 3 (1 point) List the first five terms of the sequence: 3(-1)n an n! a1 a2 = a3 = a4 = and as = Note: You can earn partial credit on this problem.Series - Sequences: Problem 4 (1 point) List the first five terms of the sequence: an a1 = 4, ant1 = an + 1 a1 a2 as = as =, and as = Note: You can earn partial credit on this problem.Series - Sequences: Problem 5 (1 point) Find a formula for the general term an of the sequence (starting with a1): 1 1 1 1 2' 4'6'8' anSeries - Sequences: Problem 6 (1 point) Determine the limit of the sequence or show that the sequence diverges by using the appropriate Limit Laws or theorems. If the sequence diverges, enter DIV as your answer. 8n2 + n + 2 an = 6n2 - 3 lim an n-+00Series - Sequences: Problem 8 (1 point) Determine the limit of the sequence or show that the sequence diverges by using the appropriate Limit Laws or theorems. If the sequence diverges, enter DIV as your answer. 7n 7 = in C" ( 6n + 4 ) \"Hear-{J Series - Sequences: Problem 7 (1 point) fix/71 Find the limit of the sequence a,x = 1 + Limit: U . If the limit does not exist, type "Diverges" or "D". Series - Ratio and Root Tests: Problem 17 (1 point) n +5 Use the ratio test to determine whether n! converges or diverges. n-7 (a) Find the ratio of successive terms. Write your answer as a fully simplified fraction. For n 2 7, lim an+1 lim n-+00 an 1-+00 (b) Evaluate the limit in the previous part. Enter oo as infinity and -oo as -infinity. If the limit does not exist, enter DNE. lim an+1 n-+00 an (c) By the ratio test, does the series converge, diverge, or is the test inconclusive? Choose

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