Question
shake(n): if(n == 1) return 0; else if(n == 2) return 1; else return n - 1 + handshake(n - 1); learn2(n): if len (n
shake(n):
if(n == 1) return 0;
else if(n == 2) return 1;
else return n - 1 + handshake(n - 1);
learn2(n):
if len (n < 2) : return O else: return int(n*(n-1)/2)
Please help me write this function
if __name__=="__main__": sys.setrecursionlimit(2000)
n = int(input("Enter max ppl:")
# Loop over values of n = 1, 2, ..., max number of people # For each n, calculuate shake(n) and learn2(n) # If shake(n) != learn2(n), print a message and exit # # The call to shake(n) must be in a try/except block that # catches any RecursionError exceptions. If the exception occurs, # print an error message (using the exception object) and print the # current recursion limit using sys.getrecursionlimit() # # After the loop, if shake(n) and learn2(n) returned the same # value for each n, then print a message indicating that the two # functions agree for the range 1 to max number of people. # # REMAINING CODE GOES HERE #
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