Show AH Work!!! 1. Find the probability value: (15 points = 5 points each) a) P(-0.32 5 z 51.62)= b) P(z>-1.03)= e) P(zg-1.35)= 2. Find the value of 20. such that: a) P( -z:: E z 5 20) = 0.82 (5 points) b) PG: E 20) = 0.9082 (5 points) 3. The random variable X is normally distributed with mean 80 and standard deviation 12. a) "What is the probability that a 1Jalue of X chosen at random will be between 7'0 and 85'? (10 points) b) What is the probability that a value of X chosen at random will be less than 75? (IllI points)