show all detailed work please

RH=(40)2h222Z2e41=me1+mnucleus1,whereme=massofelectronandmnucleus=massofnucleusRH=2.178688911018J=1.09677759107m1 Note that the value of RH in m1 is the energy in wavenumbers; this what you get when you divide RH in Joules by h and c (Planck's constant and speed of light); it corresponds to 1/, the number of waves per meter. Oftentimes cm1 is used. You may remember seeing this on IR spectra. 1. Knowing that E=RH(1121h2), please calculate the energy and wavelength of Two emission lines in the hydrogen spectrum. These two lines correspond the energy emitted when an electron in a hydrogen atom goes from nh=4 to n1=3 and nh=3 to n1=1. For each transition, specify what range of electromagnetic spectrum corresponds to the transition (UV, Vis, IR, etc)