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QUESTION 3: Answers: Two large, thin, conducting plates are given equal and opposite charges. They are then placed close together in parallel, which creates an inner surface charge density of 6.63x10-22 C/m2 per plate. The outer surface charge density is unknown. a) What is the electric field strength in between the plates? [N/C] 7.49x10 11 N/C b) What is the electric field direction in between the plates? to the left c) Use Gauss's law to determine the electric field strength outside Surface encompasses both the plates' outer surfaces (draw a Gaussian surface!). [N/C] plates -> qenc = 0 -> E =0 d) What is the outer surface charge density for the plates? [C/m?] 0 C/m ; E = (q/A), / 20 (Be sure to explain/prove your answer!) e) Use Gauss's law to prove that the plates' inner surface charge Surface cuts inside both plates density must be the same, even if they have different q's. -> Einside conductor = 0 -> Lene = 0