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QUESTION 2: Answers: A circuit comprised of 3 batteries 40 0 450 and 5 resistors is connected as WW 0.5 = 11 shown. The directions of the 2.5 = 12 three currents marked in the 2 = 13 diagram are not certain; 44 V they can point the other way 1.5 0 Alternate loop rule: outside (report as negative if they do). 44 - 401, + 151 - 52 + 15 1, - 401, -0 B a) Use the junction rule to relate the three marked currents. 1 , + 12 + 4 - 0 b) Write out the loop rule for the left loop in the circuit. 14 - 4.0 1, + 4.8 12 - 28 - 401, - 0 I, = (4.8 12 + 16.) / 8.0 c) Write out the loop rule for the right loop in the circuit. 28. - 4.8 12 + 4.51, - 52. + 151, - 0 Is = [4.8 12 + 24. ) / 6.0 d) Solve for the three currents. Report their directions with asigns { +0.500, -2.50, +2.00 } A ("+"= direction agrees with diagram). [+A] , [+A] , [#A] e) Find the potential difference: VA - VB. [V] +40.0 V