Show all work

23. A sample of n = 25 diners at a local restaurant had a mean lunch bill of $16 with a standard deviation of o = $4. We obtain a 95% confidence interval as (14.43, 17.57). Which of the following correctly interprets this interval? (2.5 pts) a. 95% of all lunches will cost between $14.43 and $17.57. b. 95% of the time, the average price for a lunch will be between $14.43 and $17.57. c. We are 95% confident that the average price for lunch is between $14.43 and $17.57. d. None of the answer options is correct