Show how the value circled in red is found. Acetone is being absorbed by pure water in a packed tower with cross sectional area $=0\mathrm{.}186m^2$ at $293K$ and $1$atm

pressure. The inlet gas mixture of air and acetone contains $2\mathrm{.}6$mol$\%$ acetone, and outlet gas contains $0\mathrm{.}5$mol$\%$

acetone. The gas flow rate is $13\mathrm{.}65$kmo$\frac{l}{h},$ and water flow rate is $45\mathrm{.}36$kmo$\frac{l}{h}.$ Given: $k_y{a}_h=0\mathrm{.}0378$

kmo$\frac{l}{s}.m^3.$mol frac. $k_x{a}_h=0\mathrm{.}0616$kmo$\frac{l}{s}*m^3.$mol frac. Equilibrium line: $y=1\mathrm{.}186($Dilute system: equilibrium line

will be straight line following Henry's law$)$

Find:

$1-$ Tower height using $k_y{a}_h$

dilute system

$h_{y{a}_h}=0\mathrm{.}0378\frac{4\text{m}\text{a}\text{l}}{s{m}^3}$

$h_{x{q}_n}=0\mathrm{.}0616\frac{4mo{l}_1}{s{m}^3}$