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Show that for a lincar triatomic molecule l b = m 1 m 2 R 1 2 2 + m 1 m 3 R 1

Show that for a lincar triatomic molecule
lb=m1m2R122+m1m3R132+m2m3R232m1m2+m3
where the atoms are labeled 1,2 and 3, and where Rij is the distance between atoms i and j. Hint: use (R13-R12-R23)2=0.
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