Question
Show that if the average depth of an n-node binary search tree is (log n) then the height of the tree is O(n log n).
Show that if the average depth of an n-node binary search tree is (log n) then the height of the tree is O(n log n). Next demonstrate that this bound is tight: there is a binary search tree with average node depth (log n) and height ( n log n).
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Data Analytics And Quality Management Fundamental Tools
Authors: Joseph Nguyen
1st Edition
B0CNGG3Y2W, 979-8862833232
