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Show that the Boolean function conjuction x 2 is not linearly separable ( i . e . there is no linear classifier sign ( w

Show that the Boolean function conjuction x2 is not linearly separable (i.e. there is no linear classifier sign(w1x1+w2x2+b) that classifies all 4 possible input points correctly). Assume that "true" is represented by 1 and "false" is represented by -1. Show that there is a linear separator for this Boolean function when we use the kernel K(x,y)conjuction(x.y)^2(x.y denotes the ordinary inner product). Give the weights and the value of b for one such separator.
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