Show that the current through two transistors in series is equal to the current through a single transistor of twice the length if the transistors are well described by the Shockley model. Specifically, show that IDS1 = IDS2 in Figure when the transistors are in their linear region: VDS < VDD - Vt, VDD > Vt (this is also true in saturation). Hint: Express the currents of the series transistors in terms of V1 and solve for V1. FIGURE Current in series transistors 1051 IDS2 VDD W/2L (a) W/L V W/L VDS VDs VDD (b)