Show that the given sequence is geometric. Then find the common ratio, and write out the first four terms. an = 13 (5 )"} Show that the sequence is geometric by showing the ratio of successive terms is a nonzero constant. an an - 1 (Type an exact answer in simplified form. Use integers or fractions for any numbers in the expression.) What is the value of the common ratio? (Type an integer or a simplified fraction.) What is the value of the first term? Find the indicated term of the geometric sequence. (Type an integer or a simplified fraction.) What is the value of the second term ? 1 1 (Type an integer or a simplified fraction.) 7th term of 1, 5' 25' What is the value of the third term? (Type an integer or a simplified fraction.) What is the value of the fourth term? Enter the 7th term of the geometric sequence. (Type an integer or a simplified fraction.) a7 = (Type an integer or a simplified fraction.) Find the fifth term and the nth term of the geometric sequence whose initial term a, and common ratio r are given a1 = 5, r=3 The fifth term of the geometric sequence is as = (Simplify your answer.) The nth term of the geometric sequence is an = (Simplify vour answer )