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show work not excel thanks 7.25 A liability of 1 is due at time 10. An attempt is made to fully immunize this liability at

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show work not excel thanks 7.25 A liability of 1 is due at time 10. An attempt is made to fully immunize this liability at io. 10 using two zero coupon bonds of amounts A and A, due at times 1 and 12, respectively. In cach of the following cases, solve for the two missing quantities out of 4.4, his given the other two (a) 11 = 5.12 = 15 (b) () 1 = 5, 4, = 40 (ii) 11 = 5, A, = 70 (no solution for t 210) (e) (1) 1 = 5, A, = 90 (two solutions for 12 2 10) (ii) 11 = 5, A, = 1,5 (one solution for 12 2 10) (iii) =5, A, = 75 (no solutions for 12 210) (d) (i) 12 =15, An =.80 (ii) 12 =15, A, = 1.1 (no solution for A, 20,0 51 510) (iii) 12 =15, A, = .01 (no solution for OS, S10) (e) A = 40, 4, = 90 the answers:- 2.2.5 (a) Ajs = .8053, Ag =.3105 (b) () 1 = 19.0530, 4, = 8432 (ii) 4,0 (c) (1) 12 = 21.28, As = 4302 or t; = 11.27. As-.1258 (ii) 12 = 31.92, As = .5056 (iii) no solution (d) (i) 4 = 9.21, 4, -2213 (ii) no solution if 4 S10 (iii) no solution (e) 4 = 4.74.17 = 20.223 show work not excel thanks 7.25 A liability of 1 is due at time 10. An attempt is made to fully immunize this liability at io. 10 using two zero coupon bonds of amounts A and A, due at times 1 and 12, respectively. In cach of the following cases, solve for the two missing quantities out of 4.4, his given the other two (a) 11 = 5.12 = 15 (b) () 1 = 5, 4, = 40 (ii) 11 = 5, A, = 70 (no solution for t 210) (e) (1) 1 = 5, A, = 90 (two solutions for 12 2 10) (ii) 11 = 5, A, = 1,5 (one solution for 12 2 10) (iii) =5, A, = 75 (no solutions for 12 210) (d) (i) 12 =15, An =.80 (ii) 12 =15, A, = 1.1 (no solution for A, 20,0 51 510) (iii) 12 =15, A, = .01 (no solution for OS, S10) (e) A = 40, 4, = 90 the answers:- 2.2.5 (a) Ajs = .8053, Ag =.3105 (b) () 1 = 19.0530, 4, = 8432 (ii) 4,0 (c) (1) 12 = 21.28, As = 4302 or t; = 11.27. As-.1258 (ii) 12 = 31.92, As = .5056 (iii) no solution (d) (i) 4 = 9.21, 4, -2213 (ii) no solution if 4 S10 (iii) no solution (e) 4 = 4.74.17 = 20.223

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