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Si se coloca 1,00 mol de argn en un recipiente de 0,500 L a 30,0 C, cul es la diferencia entre la presin ideal (segn

Si se coloca 1,00 mol de argn en un recipiente de 0,500 L a 30,0 C, cul es la diferencia entre la presin ideal (segn la prediccin de la ley de los gases ideales) y la presin real (segn la prediccin de la ecuacin de van der Waals)? Para argn, a=1,345(L2atm)/mol2 y b=0,03219L/mol.

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