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sin1(sin f) = 9 cos[(cos '3)- cos'(cos %) = 10 sin(tan %) = cos(cos 7%) = 11 sin (sin ')= sin'(sinzr) = 12 tan1(cos 7:)

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sin1(sin f) = 9 cos[(cos '3\")- cos'(cos %) = 10 sin"(tan %) = cos"(cos 7%) = 11 sin (sin '"\")= sin'(sinzr) = 12 tan1(cos 7:) = tan[(tan( (1)) = 13 COS1(COSHT\")= tan[(sin %) = 14 cos'(tan 3111371?) = cos'(sin 3%) = 15 sin (cos 51%) = sin"'(tan(%)) = 16 sin"'(sin( ) =

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