Sketch the graph of a function f satfsfying all of the following properties. a) (2 points} f is an even function with domain [5,5]. ) ( b) (3 points) f has intervals of continuity (-5, 3), [-3, 1],(1,0), (0, 1), [1, 3], (3,5). ) (3 points) f(0) = 1,f(2) =0,f(3) = 2. ) d) (3 points) Iim f(x)=1, |in;|_ f(x) =1, lim f(x)=2. x33T e) (1 point) lim f(x) =0. x+57 f) (3 points) f(x) > 0 for x in (0,2) U (3,5]. g) (3 points) f(x) o for x6 ( 3, 5 ] . ) which means, f ( ) should be greater than 2000 # 2 Here, 270, So I choose f(s ) = =2 You can choose any value for f (s ) which is greater than zero, Here, I choose 2 . ) (*) Explanation for why I choose f (1 ) = 2 : Again here, from condition (f) , we have fla) 20 fox xE (01 2 ) f ( 1 ) should be greater than zero Here, 270, 80 I choose f (1 ) = 2 . You can choose any value for f( that is greater than zero