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So, given these numbers with the average times and everything, would this be accurate? Average Times: 281+244/2= 262.5 119+131/2=125 134+143/2=138.5 138+126/2=132 109+108/2=108.5 Rates: A1= 0.001/262.5=
So, given these numbers with the average times and everything, would this be accurate? Average Times: 281+244/2= 262.5 119+131/2=125 134+143/2=138.5 138+126/2=132 109+108/2=108.5 Rates: A1= 0.001/262.5= 0.00000381 A2= 0.001/125=0.00008 A3= 0.001/138.5=0.00000722 A4= 0.005/132=0.00003788 B= 0.001/108.5= 0.00000922 m= 0.000008/0.00000381= 2.09973753 1.6/0.8=2 2.09973753/2=1.04986876 n= 0.00003788/0.00000381=9.9419391 0.005/0.001=5 9.9419391/5=1.98838782 p= 0.00000722/0.00000381= 1.89501312 0.4/0.2=2 1.89501312/2=0.94750656
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