Question
Sodium bicarbonate (NaHCO3) is the conjugate base of carbonic acid (H2CO3. pKa = 6.37). First, draw the products of the reaction of sodium bicarbonate with
Sodium bicarbonate (NaHCO3) is the conjugate base of carbonic acid (H2CO3. pKa = 6.37). First, draw the products of the reaction of sodium bicarbonate with phenol and acetic acid. Second, use your book to determine the pKa values of a phenol and a carboxylic acid. Third, determine which of these substances will react significantly (i.e.. Keq > I) with sodium bicarbonate. Explain your reasoning.
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Chemical Principles The Quest For Insight
Authors: Peter Atkins, Loretta Jones, Leroy Laverman
7th Edition
1464183953, 9781464183959
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