Solution Stoichiometry Question: You mix 40.0mL of a 0.200MFeCl3 and 60.0mL of a 0.250MNaOH. A precipitate forms based on the Net Ionic Equation, Fe3+(aq)+3OH(aq)Fe(OH)3(s) Before reaction, the Iron(III) Chloride solution generates 8.00 millimole of Fe3+ and 24.0 mmol of Cl. (you should have been able to calculate this using M ) - Calculate the mmol of Na+from the NaOH solution before reaction: - Calculate the mmol of OHfrom the NaOH solution before reaction: - Based on the Limiting lon (either Fe3+ or OH), calculate the mmol of Fe(OH)3 solid that should form