Solutions please

6, In Fig. 2, particle 1 of charge +4e is above a floor by distance d1 = 2.00 mm and particle 2 of charge +6e is on the floor, at distance d2 - 6.00 mm horizontally from particles 1. What is the x and y component of the electrostatic force on particle 2 due to particle 1. [Ans: (1.31 x 10-22 N) i - (0.437 x 10 22 N) j] MM - cm - m 0 0.00 2 mun di - 1000 12+ 6e X C = 1602 510 19 Fig. 26 mm