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Figure shows a parallel-plate capacitor with a plate area A=7.89cm2 and plate separation d= 4.62mm. A potential difference V0=80V is applied between the plates by connecting a battery between them. The top half of the gap is filled with material of dielectric constant k1=11.0; the bottom half is filled with material of dielectric constant k2=12.0. Find: (a) What is the capacitance before the dielectric dielectrics were inserted and the amount of charge on the capacitor plate? (b) What is the electric field inside the first dielectric and what is the electric field inside the 2nd dielectric? (c) What is the potential difference between the plates and the capacitance between the plates after the slab is inserted? 4. (d) What is the amount of induced charge in the dielectrics