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solve and show work CH4(g)+CCl4(g)2CH2Cl2(g) When she introduced 0.0384 moles of CH4(g) and 0.0676 moles of CCL4(g) into a 1.00 liter container, she found the

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CH4(g)+CCl4(g)2CH2Cl2(g) When she introduced 0.0384 moles of CH4(g) and 0.0676 moles of CCL4(g) into a 1.00 liter container, she found the equilibrium concentration of CCl4(g) to be 0.0625M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc=

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