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solve for maximum temperature RT=Rrt11+a (T-Trt)l Tl = 9.20 [1 +4.5*10 I (T - 20.90) Cl = 266.00 = [1 + 1040c-l (T - 20.90)
solve for maximum temperature
RT=Rrt11+a (T-Trt)l Tl = 9.20 [1 +4.5*10 I (T - 20.90) Cl = 266.00 = [1 + 1040c-l (T - 20.90)
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