solve from 1 to 4

and show the hand work

Suppose that the subkey for the current round is this 48 bit number: 000000100000000000000000000000000000000000000000 What does the 64 bit state look like after the IP transforma- 2. (1 point) tion is applied to the input? This question concerns the DES S-boxes. Please enter all answers in decimal. Consider the two 6-bit numbers x1=111101 and x2= Now find L0 and R0, the left and right halves of the state. 111001. What is S1(x1) ? (in decimal) L0= R0= What is the result of applying the expansion box to R0 ? E(R0)= What is the result of XORing the subkey with E(R0) ? k0E(R0)= We now apply the S-box transformation. S(k0E(R0))= Finally we apply the permutation box to complete the func- This shows that S1 is non-linear with respect to x1 and x2. Answer (s) submitted: f(R0)=P(S(k0E(R0)))= We can now compute the state of DES going into the next round. L1=R1= Answer(s) submitted: 3. (1 point) This question concerns the DES IP box. Please enter all answers as strings of 0 's and 1's. Consider the 64 bit DES block below. 0001000110001000000000000000000000000000000000100000000000000000 Suppose that this is the initial input to DES. What will the block look like after the initial permutation (IP) is applied