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solve it with pf=0.5 leading A transformer is rated 500 kVA, 2400:480 V, 60 Hz. The impedances (a ohms) of the equivalent circuit for this

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solve it with pf=0.5 leading
A transformer is rated 500 kVA, 2400:480 V, 60 Hz. The impedances (a ohms) of the equivalent circuit for this transformer are as follows, where the subscript 1 is used for the high-voltage winding and 2 for the low-voltage winding: 11=0.058 12=0.002 * = 400 X;=0.29 x2 = 0.012 r=2000 The load is connected across the low-voltage winding and draws rated current at 0.866 pF lagging with rated voltage at the terminals of this winding. For this condition of loading, determine the high-voltage winding terminal voltage current, and power factor and the transformer efficiency. The turnerin Also calculate voltage regulation under this load

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