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solve please................................................. 1. Which is better, a score of 92 on a test with a mean of 71 and a standard deviation of 15I or

solve please.................................................

1.

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Which is better, a score of 92 on a test with a mean of 71 and a standard deviation of 15I or a score of 688 on a test with a mean of 493 and a standard deviation of 150? O A. A score of 92 O B. A score of 688 O 0. Both scores have the same relative position. A nationwide study of Amen'oan homeowners revealed lha1659'a have one or more lawn mowers. A lawn equipment manufacturer, located 1'n Omaha. feels the estimate 15 too low for households in Omaha. Find the Prvalue for a test ho support the claim thatthe proportion with lawn mowers in Omaha 1': higherfhan 65%. Among 497 randomly selected homes in Omaha, 340 had one or more lawn mowers. Round to four declmal places. 0 A. 0.0559 0 a. 0.9441 0 c. 0.0252 0 D. 0.111s The tesi scores of 32 students are listed below. Construct a Wot for the data set. Include values ofthe 5-nu mber sur'l'1mar3.r in all boxplots. % 323?414446435355 5? 5? 59 63 55 66 63 69 1'0 1'2 7'2 1'3 73 T5 1'8 1'9 B132 83 86 39 92 95 99 on. 03. ' l 32 56 69.5 80 95 32 56 61.5 so 99 OS. on. 32 56 69. 5 79 99 32 56 69. 5 80 99 The annuai snowfall in a town has a mean of 39 ineh and a standard deviation of 11 inches. Last year there were 69 inches of snow. How many standard deviations from the mean is that? Round your answer to two decimal places. 0 A. 2.73 standard deviations above the mean 0 B. 0.41 standard deviations below the mean 0 c. 2.73 standard deviations below the mean 0 D. 0.41 standard deviations above the mean Assume thata simple random sample has been selected from a normally distributed population and test the given claim. Identify the null and altemative hypothesesI test statistic. Pivalue, and state the final conclusion that addresses the original claim. A simple mndom sample cf25 ltered 100 mm cigarettes is obtained. and the tar content ol'each cigarette is measured. The sample has a mean of19.6 mg and a standard deviation of 3.31 mg. Use a 0.05 signicance level to tes1 the daim that the mean tar content of ltered 100 mm cigarettes is less than 21.1 mg, which is the mean for unltered king size cigarettes. What do the results suggest. ifanything, about the effectiveness of the lters? What are the hypotheses? OA. H01u=21.1mg OE. H01p21.1mg OD. Ho:p=21.1 mg H11u

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