Question
Solve the following recurrence relations using the repeated substitution method: T(n) = T(n/2) + 1 when n 1, T(1) =1 T(n) = T(n/2) + n
Solve the following recurrence relations using the repeated substitution method: T(n) = T(n/2) + 1 when n 1, T(1) =1 T(n) = T(n/2) + n when n 1, T(1) =1 T(n) = T(n-1) + 1 when n 1, T(1) =1 T(n) = T(n-1) + n when n 1, T(1) =1 T(n) = 2T(n-1) + 1 when n 1, T(1) =1 T(n) = T(n-1) * n when n 1, T(1) =1
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Database And Expert Systems Applications 31st International Conference Dexa 2020 Bratislava Slovakia September 14 17 2020 Proceedings Part 1 Lncs 12391
Authors: Sven Hartmann ,Josef Kung ,Gabriele Kotsis ,A Min Tjoa ,Ismail Khalil
1st Edition
303059002X, 978-3030590024
