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Solve the Following using linear substitutions: y = 1+x+y + xy y(x) cez ce(x+2) -1 y' = (1 - y) cos x y(r) ce-sin(x)

Solve the Following using linear substitutions: y = 1+x+y + xy y(x) cez ce(x+2) -1 y' = (1 - y) cos x y(r) ce-sin(x) +1

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Starting with the equation y 1 x y xy we can rearrange to get y xy 1 x y Factoring out y on the left ... blur-text-image

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