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Solve the initial- value problem: dy/dt = y^2sint^2, y(-2) = 1/3 Marks (15) Please note that it must be sint^2 and NOT sin^2t.
Solve the initial- value problem:
dy/dt = y^2sint^2, y(-2) = 1/3 Marks (15)
Please note that it must be sint^2 and NOT sin^2t.
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