solve......

The mean number of English courses taken in a two-year time period by male and female college students is believed to be about the same. An experiment is conducted and data are collected from 29 males and 16 females. The males took an average of two English courses with a standard deviation of 0.9. The females took an average of three English courses with a standard deviation of 1.1. Are the means statistically the same? (Use a = 0.05) NOTE: If you are using a Student's t-distribution for the problem, including for paired data, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) Part (a) State the null hypothesis. O Ho: HM 2 HF O HO: HM HF + Part (b) Part (c) In words, state what your random variable XM - XF represents. O XM- XF represents the mean difference in the number of English courses taken by males and females. O XM- XF represents the difference in number of English courses taken by males and females. O XM - XF represents the mean number of English courses taken by males and females. O XM - XF represents the difference in the mean number of English courses taken by males and females. Part (d) State the distribution to use for the test. (Enter your answer in the form z or tay where df is the degrees of freedom. Round your answer to two decimal places.)