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Solve the recurrence relation subject to the initial conditions. F(1) = -10 F(2) = 40 F(n) = -10F(n-1) - 25F(n-2) for n 3

Solve the recurrence relation subject to the initial conditions. F(1) = -10 F(2) = 40 F(n) = -10F(n-1) - 25F(n-2) for n 3

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