solve.....
While her husband spent 21/2 hours picking out new speakers, a statistician decided to determine whether the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment. The population was Saturday afternoon shoppers. Out of 68 men, 24 said they enjoyed the activity. Eight of the 23 women surveyed claimed to enjoy the activity. Interpret the results of the survey. Conduct a hypothesis test at the 5% level. Let the subscript m = men and w = women. NOTE: If you are using a Student's t-distribution for the problem, including for paired data, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) Part (a) + Part (b) Part (c) + Part (d) Part (e) What is the test statistic? (If using the z distribution round your answer to two decimal places, and if using the t distribution round your answer to three decimal places.) ---Select--- O= Part (f) What is the p-value? (Round your answer to four decimal places.) Explain what the p-value means for this problem. O If Ho is false, then there is a chance equal to the p-value that the proportion of men who enjoy shopping for electronic equipment is at least 0.0051 higher than the proportion of women who enjoy shopping for electronic equipment. O If Ho is true, then there is a chance equal to the p-value that the proportion of men who enjoy shopping for electronic equipment is 0.0051 lower than the proportion of women who enjoy shopping for electronic equipment. O If Ho is true, then there is a chance equal to the p-value that the proportion of men who enjoy shopping for electronic equipment is at least 0.0051 higher than the proportion of women who enjoy shopping for electronic equipment. O If Ho is false, then there is a chance equal to the p-value that the proportion of men who enjoy shopping for electronic equipment is 0.0051 lower than the proportion of women who enjoy shopping for electronic equipment