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Some Critical Values that could be Useful: t0_25.19 = 2-093: fn.121.7.12 = 2-12, X31152 = 5-991:Xg.o25,1 = 7373130.!)133 = 2-445 Problems: 3. The Orange data

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Some Critical Values that could be Useful: t0_25.19 = 2-093: fn.121.7.12 = 2-12, X31152 = 5-991:Xg.o25,1 = 7373130.!)133 = 2-445 Problems: 3. The Orange data set in R given the age (days) and circumference (mm) as records of the growth of orange trees. Now, we use the age as the predictor and the circumference as the response variable. It can be calculated that, for n = 35 sample, I: X; = 32275. 2 Y; = 4055, 2 X5}? = 4617544, 2 X1? = 3?937805 and Z Y? = 532167. Based on these data, (a) (15 pt} Fit- a simple linear regression model, i.e., nd 30 and 31. (b) (10 pt} Find 53. What is the degrees of freedom? (c) (10 pt} Find R2. (d) (15 pt) Test for Ho : {i1 = 0 against H. :51 95 0 using or = 0.05

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