Someone please help me, I had been kept on uploading this question for more than 7-9 time, with a desperate needed of help. Luckily someone did manage to help me out but I don't understand how this person got the answer. So, now I upload the same question again. This time, instant of answering the question, could you please just show me how this person got the answer by showing step-by-step solving. Pretty much explaining how this person got the answer
I had attached the original question as well as the ANSWER.
Please help me. I'm really having trouble solving this one.
The actual question
Analyse: Choose one valid method to evaluate how normal your population data is for both the selected data sets. (just use the diagonal length)
Calculate the mean and standard deviation of the population data.
Calculate the mean and standard deviation of an SRS of size n=8.
Explain how you ensured that the samples were SRS.
DATA
Paper 1 Paper 2 Paper 3 Paper 4 Diagonal 247mm Diagonal 247.5mm Diagonal 247mm Diagonal 247.5mm Side 1 - 175mm Side 1 - 175.5mm Side 1 - 175.5mm Side 1 - 175.5mm Side 2 - 175mm Side 2 - 176mm Side 2 - 175mm Side 2 - 176mm Side 3 - 175.5mm Side 3 - 175.5mm Side 3 - 175.5mm Side 3 - 175.5mm Side 4 - 175.5 mm Side 4 - 176 mm Side 4 - 175.5 mm Side 4 - 176 mm Diagonal 247.5mm Diagonal 247.3mm Diagonal 247.5.mm Diagonal 249mm Data Side 1 - 175mm Side 1 - 175 Side 1 - 175 Side 1 - 175 Side 2 - 175mm Side 2 - 175.8 Side 2 - 175.2 Side 2 - 176 Side 3 - 175mm Side 3 - 174.5 Side 3 - 175 Side 3 - 176.8 Side 4 - 175 mm Side 4 - 175 Side 4 - 175 Side 4 - 177 Diagonal 247.5mm Diagonal 248.9mm Diagonal 248.9mm Diagonal 247.5mm Side 1 - 175 Side 1 - 174 Side 1 - 175 Side 1 - 175 Side 2 - 175 Side 2 - 174 Side 2 - 175 Side 2 - 175 Side 3 - 175 Side 3 - 175 Side 3 - 176 Side 3 - 175 Side 4 - 175 Side 4 - 176 Side 4 - 176 Side 4 - 175Choosing the variable of interest to be the liegonal length: Mean of pop: 2413583 Stdeu of pop: 0301734 Mean of sample: 241975 Stdev of sample: 0.311964 Explenem Letting di=diagonal length of the ith piece of paper _ 12 ._1.L Mean of pop: \"0' _ EH 12 = 247.7533 212 (drag): "=1 12 0301734 Stdev 01 pop: To get a simple random sample of size a. we can simply use a random number generator such as the RANDO function in Excel. This function allows me to assign a random number to each observation. then I sort the data based on the random numbers and select the top 8 for my simple random sample (without replacement). What I got from Excel was: Diagonal Length Random number 247 0.624468 247.5 0.077057 24? 0.307428 247.5 0.073506 247.5 0.446381 247.3 0.185621 247.6 0-54-2658 249 0.582861 247.5 0.337025 248.9 0.797399 243.9 0.616534 247.6 0.453687 Thus I choose those in held to be part of my sample. Mean el sample: Stdev 01 sample: Note that the denominator for the standard deviation of a sample is n-1 and net n to ensure unbiasedness. d =2 3 a i=1 3 =241975 2.1. (47"? E" - 0.701734