Question
Sorting Algorithms [60 points] In Sorting class, define two methods reverseSelectionSort(Comparable list) and reverseInsertionSort(Comparable list)that sort elements in descending order. Create a driver class called
Sorting Algorithms [60 points]
In Sorting class, define two methods reverseSelectionSort(Comparable list) and reverseInsertionSort(Comparable list)that sort elements in descending order.
Create a driver class called SortingTest, whose main method 1) prompts users to enter five string values separated by space, 2) store the strings in an array and 3) sort the arrays using the methods in Sorting class.
Sample Run:
Enter five string values: paper true soap floppy flower
Using Selection Sort to Sort Strings in Ascending Order floppy, flower, paper, soap, true
Using Selection Sort to Sort Strings in Descending Order true, soup, paper, flower, floppy
Using Insertion Sort to Sort Strings in Ascending Order floppy, flower, paper, soap, true
Using Insertion Sort to Sort Strings in Descending Order true, soup, paper, flower, floppy
This is the starting code I have been given
//******************************************************************** // Sorting.java Author: Lewis/Loftus // // Demonstrates the selection sort and insertion sort algorithms. //********************************************************************
public class Sorting
// One by one look at the elements of list for (int index = 0; index < list.length-1; index++) { // find the minimum element in the remaining part of list min = index; for (int scan = index+1; scan < list.length; scan++) if (list[scan].compareTo((T)list[min]) < 0) min = scan;
// Swap the minimum with the current value temp = list[min]; list[min] = list[index]; list[index] = temp; } }
//----------------------------------------------------------------- // Sorts the specified array of objects using the insertion // sort algorithm. //----------------------------------------------------------------- public void insertionSort (Comparable
// Move elements of list, that are larger than key, to one position ahead of their current position while (position > 0 && key.compareTo((T)list[position-1]) < 0) { list[position] = list[position-1]; position--; }
list[position] = key; } } }
If someone could help that would be great!
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