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standard deviation of = 14 minutes and a normal distribution. A random sample of 23 bulls had a mean tranquilized duration time of close to
standard deviation of = 14 minutes and a normal distribution. A random sample of 23 bulls had a mean tranquilized duration time of close to 65 minutes but a standard deviation of 19 minutes. At the 5% level of significance, is the veterinarian justified in the claim that the standard deviation is larger than the drug company specifications? 1) state the hypothesis 2)Compute the test statistic. Include if it is z, t or . 3)Find the critical value(s) OR the p-value. Make the decision about the null hypothesis. (Conclude the test.)
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