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Standard Deviations =76.766805 n = 67 Mean = 56.33209 At a recent meeting, the manager of a national call center for a major Internet bank
Standard Deviations =76.766805
n =
67
Mean = 56.33209
At a recent meeting, the manager of a national call center for a major Internet bank made the statement that the average past-due amount for customers who have been called previously about their bills is now no larger than $38.00. Other bank managers at the meeting suggested that this statement may be in error and that it might be worthwhile to conduct a test to see if there is statistical support for the call center manager's statement. The accompanying table contains data for a random sample of 67 customers from the call center population. Assuming that the population standard deviation for past due amounts is known to be $50.00, what should be concluded based on the sample data? Test using a = 0.10. Click the icon to view the data table. State the appropriate null and alternative hypotheses. Choose the correct answer below. O A. Hy: HI s 38.00 O B. Hy: pl z 38.00 O C. Hy: P# 38.00 HA: p > 38.00 HA: HI 38.00 OF. Hy: HStep by Step Solution
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