Start with a circle of radius r=15. Form the two shaded regions pictured below. Let f(9) be the area of the shaded region on the left which has an arc and two straight line sides. Let 9(9) be the area of the shaded region on the right which is a right triangle. Note that the areas of these two regions will be functions of 9; r=15 is fixed in the problem. f(0) 9(0) (a) Find a formula for f(6)= (b)Find a formula for 9(6): (c) (1)1111} f (H): (d) llanilly (H): lim (e) 040 [f(6)/g(9)]=